The Position of a particle as a function of time is described as yt=3t2+2t+4. What is the average velocity of the particle from t=0 S to t=2 S
8 m/s
4 m/s
2 m/s
1 m/s
Given y(t)=3t2+2t+4y(0)=0+0+4=4my(2)=3(2)2+2(2)+4=12+4+4=20m∴ averagevelocity V=y(2)−y(0)t2−t1 =20−42−0 =162=8m/s