Questions
The position of a particle moving in a straight line is given by . Here x is in m, and ‘t’ in second. Then
a
Direction of velocity and acceleration both change at t=2 sec
b
The distance travelled by particle is equal to magnitude of displacement for t = 0 to t = 5
c
The speed of particle is decreasing in t= 0 to t = 2sec then it is increasing for t>2
d
The magnitudes of velocity and acceleration are equal at t = 0
detailed solution
Correct option is B
x=3t3−18t2+36t v=dxdt=9t−22⇒a=18t−2Talk to our academic expert!
Similar Questions
Particle located at x = 0 at time t = 0, starts moving along the positive x-direction with a velocity v that varies as . The displacement of the particle varies with time as
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