The position of a particle at time t is given by the relation $$x(t)$$ $$=$$ (vo$$α$$)(1-e-$$α$$t), where $$v0$$ is a constant and α > $$0$$. The dimensions of $$v0$$ and α are respectively

Correct option is 1M0L1T-1 and T-1

Questions

The position of a particle at time t is given by the relation $x (t) = (\frac{v_{o}}{α}) (1 - e^{- αt}),$ where $v_{0}$ is a constant and $α > 0$ . The dimensions of $v_{0} and α$ are respectively

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M0L1T-1 and T-1

M0L1T0 and T-1

M0L1T-1 and LT-2

M0L1T-1 and T

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detailed solution

Correct option is A

Dimensions of αt = [M0L0T0] ∴ [α] = [T-1]Again [v0α] = [L] so [vo] = [LT-1]

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The position of a particle at time t is given by the relation x(t) = (voα)(1-e-αt), where v0 is a constant and α > 0. The dimensions of v0 and α are respectively

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The position of a particle at time t is given by the relation $x (t) = (\frac{v_{o}}{α}) (1 - e^{- αt}),$ where $v_{0}$ is a constant and $α > 0$ . The dimensions of $v_{0} and α$ are respectively