The position of a projectile launched from the origin at t = 0 is given by $\overrightarrow{\mathrm{r}}=(40\widehat{\mathrm{i}}+50\widehat{\mathrm{j}})\mathrm{m}\text{ at }\mathrm{t}=2\mathrm{s}$. If the projectile was launched at an angle $\mathrm{\theta }$ from the horizontal, then $\mathrm{\theta }$ is (take g = 10 ms^-2)

• A

  ${\tan }^{-1}\frac{2}{3}$

• B

  ${\tan }^{-1}\frac{3}{2}$

• C

  ${\tan }^{-1}\frac{7}{4}$

• D

  ${\tan }^{-1}\frac{4}{5}$