Questions
The position of projectile launched from the origin at t=0 is given by m at t = 2s. If the projectile was launched at an angle from the horizontal, then is (take g = 10 m/s2).
detailed solution
Correct option is C
The position vector of the projectile is r→=u→t+12a→t240 i^+50j^=u→×2+12−10j^×22⇒u→=uxi^+uyj^=20 i^+35j^tanθ=uyux=3520=74⇒θ=tan−174Talk to our academic expert!
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A ball is projected obliquely with a velocity 49 ms–1 strikes the ground at a distance of 245 m from the point of projection. It remained in air for
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