Q.

The position vector of a particle bis r→=[2i+3j+k  while its linear momentum is p→ = (2i+3j+k). Then its  angular momentum about the origin is

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a

2i-4k

b

4i-8k

c

2i-4j+2k

d

4i-8j

answer is B.

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Detailed Solution

We know that L = r x PHere r=4j and p=2i+3j+k∴L=r×p=4j×(2i+3j+k)=4i−8k
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The position vector of a particle bis r→=[2i+3j+k  while its linear momentum is p→ = (2i+3j+k). Then its  angular momentum about the origin is