First slide

Instantaneous velocity

Question

The position vector of a particle moving in xy plane is given by $\vec{r} = (t^{2} - 4) \hat{i} + (t - 4) \hat{j}$ .Time when it crosses y-axis

Easy

A

1 sec
B

2 sec
C

3 sec
D

4 sec

Solution

While crossing Y axis, the X-coordinate of $\vec{r} = 0$
$t^{2} - 4 = 0 \Rightarrow t = 2 \sec$

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