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Q.

The position vector of a particle R→ as a function of time is given by R→=4sin(2πt)i^+4cos(2πt)j^Where R is in meters, t is in seconds and i^ and j^ denote unit vectors along x-and y-directions, respectively. Which one of the following statements is wrong for the motion of particle?

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a

Magnitude of the velocity of particle is 8 meter/second.

b

Path of the particle is a circle of radius } 4 \text { meter.

c

Acceleration vector is along -R→ .

d

Magnitude of acceleration vector is v2R, where v is the velocity of particle.

answer is A.

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Detailed Solution

Here, R→=4sin(2πt)i^+4cos(2πt)j^The velocity of the particle isv→=dR→dt=ddt[4sin(2πt)i^+4cos(2πt)j^]=8πcos(2πt)i^-8πsin(2πt)j^its magnitude is|v→|=(8πcos(2πt))2+(-8πsin(2πt))2=64π2cos2(2πt)+64π2sin2(2πt)=64π2cos2(2πt)+sin2(2πt)=64π2                                        as sin2θ+cos2θ=1=8πm/s
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