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The position x of a particle varies with time t as $x = {at}^{2} - {bt}^{3}$ .The acceleration of the particle will be zero at time t equal to

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2a3b

a3b

Zero

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Correct option is C

dxdt=2at−3bt2⇒d2xdt2=2a−6bt=0⇒t=a3b

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The position x of a particle varies with time t as x=at2−bt3.The acceleration of the particle will be zero at time t equal to

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Ready to Test Your Skills?

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The position x of a particle varies with time t as $x = {at}^{2} - {bt}^{3}$ .The acceleration of the particle will be zero at time t equal to