The position x of a particle varies with time t as x=at2−bt3. The acceleration of the particle will be zero at time t equal to
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
ab
b
2a3b
c
a3b
d
zero
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
given Position of particle x=at2−bt3differentiate w.r.t. time t to get velocity velocity =dxdt=dat2−bt3dt⇒v=2at−3bt2again differentiate w.r.t. time t to get acceleration Acceleration =dvdta=d2at−3bt2dt⇒2a−6bt Acceleration will become zero O=2a−6bt⇒2a=6bt⇒t=a3b=time in which acceleration becomes zero