Questions
The position x of a particle varies with time t as . The acceleration of the particle will be zero at time t equal to
detailed solution
Correct option is C
given Position of particle x=at2−bt3differentiate w.r.t. time t to get velocity velocity =dxdt=dat2−bt3dt⇒v=2at−3bt2again differentiate w.r.t. time t to get acceleration Acceleration =dvdta=d2at−3bt2dt⇒2a−6bt Acceleration will become zero O=2a−6bt⇒2a=6bt⇒t=a3b=time in which acceleration becomes zeroTalk to our academic expert!
Similar Questions
Particle located at x = 0 at time t = 0, starts moving along the positive x-direction with a velocity v that varies as . The displacement of the particle varies with time as
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