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Q.

The position x of a particle varies with time (t) as x=at2−bt3. The acceleration at time t of the particle will be equal to zero, where t is equal to

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a

2a3b

b

ab

c

a3b

d

zero

answer is C.

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Detailed Solution

x=at2−bt3 Velocity =dxdt=2at−3bt2 and acceleration =d2xdt2=2a−6bt Acceleration will be zero if 2a−6bt=0⇒t=2a6b=a3b
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