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The position x of a particle varies with time t as x = at2 – bt3. The acceleration of the particle will be zero at time t equal to

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a
a/b
b
2a/3b
c
a/3b
d
Zero

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detailed solution

Correct option is C

Position x = at2 - bt3Velocity =dxdt= ddt(at2- bt3)Velocity = 2ta - 3bt2Acceleration = dvdt= ddt(2at-3bt2)Acceleration = 2a - 6bt = 02a = 6bt ⇒t = a/3b


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