Questions

The position x of a particle with respect to time t along X-axis is given by where x is in metre and t in second. What will be the position of this particle when it achieves maximum speed along the + X direction?

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By Expert Faculty of Sri Chaitanya
a
32 m
b
54 m
c
81 m
d
24 m

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detailed solution

Correct option is B

x=9t2-t3v=dxdt=18t-3t2a=dvdt=18-6tWhen   a=0,   v=maximum 18=6t   t=3secx=9×32-33=81-27=54m

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A physical quantity A is related to four observable a, b, c and d as $\mathrm{A}=\frac{{\mathrm{a}}^{2}{\mathrm{b}}^{3}}{\mathrm{c}\sqrt{\mathrm{d}}}$ . The percentage errors of measurement in a, b, c and d are 1 %, 3 %, 2 % and 2 % respectively. What is the percentage error in the quantity A ?

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