The position x of a particle with respect to time t along X-axis is given by x = 9t2 – t3 where x is in metre and t in second. What will be the position of this particle when it achieves maximum speed along the + X direction?

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32 m

54 m

81 m

24 m

answer is B.

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Detailed Solution

x=9t2-t3v=dxdt=18t-3t2a=dvdt=18-6tWhen a=0, v=maximum 18=6t t=3secx=9×32-33=81-27=54m

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