The position 'y' of a particle varies with time (t) as y=at3−bt2. The acceleration at time of the particle will be equal to zero, where ‘t’ is equal to
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a
3ab
b
b3a
c
3ba
d
a3b
answer is B.
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Detailed Solution
Given that y=at3−bt2 ∴ Velocity V=dydt =3at2−2bt acceleration a=dvdt=6at−2b∴ If a=0 i.e 6at−2v=0⇒6at=2b⇒t=2b6a=b3a