A positive charge +q1 is located to the left of a negative charge -q2. On a line passing through the two charges, there are two places where the total potential is zero. The reference is assumed to be at infinity. The first place is between the charges and is 4.00 cm to the left of the negative charge. The second place is 7.00 cm to the right of the negative charge. If q2=−12μC and q1=11×xμC, what is the value of charge x.
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answer is 4.
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Detailed Solution
q1x−4−q24=0 q1x+7−q27=0or q1q2=x−44 q1q2=x+77∴ x−44=x+77or 7x−28=4x+28 or 3x=56 or x=563or q1q2=563+77=113or q2=+12μcor q1=12×113=44μC=11×4μC