A positive point charge 50 μC is located in the plane xy at a point with radius vector r→0=2i^+3j^. The electric field vector, E→ at a point with radius vector r→=8i^−5j^, where r0 and r are expressed in meter, is
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a
(1.4i^−2.6j^)kNC−1
b
(1.4i^+2.6j^)kNC−1
c
(2.7i^−3.6j^)kNC−1
d
(2.7i^+3.6j^)kNC−1
answer is C.
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Detailed Solution
As E→=14πε0qr→−r→03r→−r→0 MN→=r→−r→0=(i^−5j^)−(2i^+3j^)=(6i^−8j^)r→−r→0=62+82=10mE→=9×109×50×10−6(10)3(6i^−8j^)E→=(2.7i^−3.6j^)kNC−1