First slide

Electric field

Question

A positively charged ball hangs from a long silk thread. Electric field at a certain point (at the same horizontal level of ball) due to this charge is E. Let us put a positive test charge q₀ at this point and measure F/q₀ on this charge. Then, E

Moderate

A

> F/q₀
B

< F/q₀
C

=F/q₀
D

none of these

Solution

$E = \frac{k Q}{r^{2}} . . . . . . . . . . . . (i)$
$F = \frac{k Q q_{0}}{r_{1}^{2}} or \frac{F}{q_{0}} = \frac{k Q}{r_{1}^{2}} . . . . . . . . . . . (i i)$
As r₁ > r, so from Eqs. (i) and (ii), we get E > F/q₀

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