Questions
The potential barrier developed in the diode shown in figure below is 0.5 V. The current through the diode is
a
45 mA
b
40 mA
c
30 mA
d
20 mA
detailed solution
Correct option is C
I=5−0.5150A=4.5150A =0.03 A=30 mATalk to our academic expert!
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In a pn junction diode, the thickness of depletion layer is 2 x 10-6m and barrier potential is 0.3v. The Intensity of the electric field at the junction is —
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