A potential barrier V volts exists across a P-N junction. The thickness of the deplection region is ‘d’. An electron with velocity ‘V’ approaches P-N junction from N-side. The velocity of the electro a crossing the junction is
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a
V2+2Vem
b
V2−2Vem
c
V
d
2Vem
answer is B.
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Detailed Solution
V2=u2−2as⇒Vf2=Vi2−2.eEm.dPuting values of Vi and Ed we get Vf=V2−2Vem