X-rays

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Question

The potential difference across the Coolidge tube is 20 kV and 10 mA current flows through the voltage supply. Only 0.5% of the energy carried by the electrons striking the target is converted into X-rays. The power carried by X-ray beam (in W) is ______

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Solution

$\begin{array}{l} Power of electron beam is P = V i = 20 \times 10^{3} \times 10 \times 10^{- 3} \\ \Rightarrow P = 200 W \\ \Rightarrow P_{X - ray} = \frac{0.5}{100} \times 200 = 1 W \end{array}$

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