Download the app

Questions  

The potential difference across the 100  Ω resistance in the following circuit is measured by a voltmeter of 900  Ω resistance. The percentage error made in reading the potential difference is

a
109
b
0.1
c
1.0
d
10.0

detailed solution

Correct option is C

Before connecting the voltmeter, potential difference across 100  ΩVi=100100+10  ×  V=1011 VFinally after connecting voltmeter across 100  ΩEquivalent resistance 100 × 900100+900  90  ΩFinal potential difference,Vf= 9090+10 × V=910 V %  error =Vi −VfVi  ×  100=1011  V  −  910 V1011  V ×  100 =  1.0 %

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

In the given circuit, the voltmeter records 5 volt. The resistance of the voltmeter in ohms is


phone icon
whats app icon