Questions
The potential difference across the resistance in the following circuit is measured by a voltmeter of resistance. The percentage error made in reading the potential difference is
detailed solution
Correct option is C
Before connecting the voltmeter, potential difference across 100 ΩVi=100100+10 × V=1011 VFinally after connecting voltmeter across 100 ΩEquivalent resistance 100 × 900100+900 90 ΩFinal potential difference,Vf= 9090+10 × V=910 V % error =Vi −VfVi × 100=1011 V − 910 V1011 V × 100 = 1.0 %Talk to our academic expert!
Similar Questions
In the given circuit, the voltmeter records 5 volt. The resistance of the voltmeter in ohms is
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