The potential difference across the 100  Ω resistance in the following circuit is measured by a voltmeter of 900  Ω resistance. The percentage error made in reading the potential difference is

Before connecting the voltmeter, potential difference across 100  ΩVi=100100+10  ×  V=1011 VFinally after connecting voltmeter across 100  ΩEquivalent resistance 100 × 900100+900  90  ΩFinal potential difference,Vf= 9090+10 × V=910 V %  error =Vi −VfVi  ×  100=1011  V  −  910 V1011  V ×  100 =  1.0 %