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The potential difference applied between the filament and target in a Coolidge tube is 13.6 kV. It is observed that the wavelength of Kα characteristic X-rays is three times the cut off wave length. The atomic no. of target element is

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answer is 22.

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Detailed Solution

λcutoff=hceV, for Kαλkα=hcEK−ELhcEK−EL=3hceV⇒eV3=EK−EL=−13.6 (Z-1)214−1V3=13.6(Z-1)2×34(Z-1)2=4×13.6×1039×13.6Z=22

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