Questions
The potential difference applied to an X-ray tube is V. The ratio of the de Broglie wavelength of electron to the minimum wavelength of X-ray is directly proportional to
detailed solution
Correct option is B
de Broglie wavlength=λ=h2meVLet say cut off wavelength =λmin⇒hcλmin=eVMultiplying we get,λ×hcλmin=h2meVeV ⇒λλmin∝VTalk to our academic expert!
Similar Questions
In X-ray tube, when the accelerating voltage V is halved, the difference between the wavelength of line and minimum wavelength of continuous X-ray spectrum
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