The potential difference applied to an X-ray tube is V. The ratio of the de Broglie wavelength of electron to the minimum wavelength of X-ray is directly proportional to
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a
V
b
V
c
V3/2
d
V7/2
answer is B.
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Detailed Solution
de Broglie wavlength=λ=h2meVLet say cut off wavelength =λmin⇒hcλmin=eVMultiplying we get,λ×hcλmin=h2meVeV ⇒λλmin∝V