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Potential difference between the ends of a current carrying conductor of length 50 cm is 10 volt. If the drift velocity of free electrons in the conductor is $8 \times 10^{- 5} m / s$ , find the mobility of electrons in $m^{2} V^{- 1} S^{- 1}$ .

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detailed solution

Correct option is C

Electric field inside the conductor E=Vl=100.5Vm=20 Vm∴ Mobility μ=VdE∴ μ=8×10−520m2V−1S−1=4×10−6m2V−1S−1

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Potential difference between the ends of a current carrying conductor of length 50 cm is 10 volt. If the drift velocity of free electrons in the conductor is 8×10−5m/s, find the mobility of electrons in m2V−1S−1.

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Potential difference between the ends of a current carrying conductor of length 50 cm is 10 volt. If the drift velocity of free electrons in the conductor is $8 \times 10^{- 5} m / s$ , find the mobility of electrons in $m^{2} V^{- 1} S^{- 1}$ .