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Q.

Potential difference between the ends of a current carrying conductor of length 50 cm is 10 volt. If the drift velocity of free electrons in the conductor is 8×10−5m/s, find the mobility of electrons in m2V−1S−1.

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a

8.45×10−6

b

2.15×10−6

c

4×10−6

d

6×10−5

answer is C.

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Detailed Solution

Electric field inside the conductor E=Vl=100.5Vm=20 Vm∴ Mobility μ=VdE∴ μ=8×10−520m2V−1S−1=4×10−6m2V−1S−1
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