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Q.

The potential difference V and the current i flowing through an instrument in an ac circuit of frequency f are given by V=5cosω t volts and I = 2 sin ω t amperes (where ω=2πf). The power dissipated in the instrument is

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a

Zero

b

10 W

c

5 W

d

2.5 W

answer is A.

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Detailed Solution

V=5cosω t=5sinω t+π2  and i=2sinω tPower  =Vr.m.s.×ir.m.s.×cosφ= 0(Since φ=π2, therefore cosφ=cosπ2=0)
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