Questions
A potential difference of 6000 V is maintained between two large parallel plates 6cm apart. The force on a proton midway between the plates is
detailed solution
Correct option is B
force on charge particle is F=Eqbut electric field is E=Vdtherefore F=Vqd=6000×1.6×10-196×10-2F=16×10-15 NTalk to our academic expert!
Similar Questions
A charge of 5C experiences a force of 5000N when it is kept in a uniform electric field. What is the potential difference between two points separated by a distance of 1cm
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