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Q.

Potential drop across a 10Ω resistor is found to be v=25±1volt and the current flowing through it is measured as i=5 ±  0.1A. Then the maximum permissible error in power consumed by the resistor is

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a

3%

b

4%

c

2%

d

6%

answer is D.

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Detailed Solution

(4)P=Vi ⇒  ΔPPmax  ×  100%  =  ΔVV  ×  100%  +Δii×  100%=125×  100%  +  0.15×  100%=6%
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