The potential energy of a certain spring when stretched through a distance ‘S’ is 10 joule. The amount of work (in joule) that must be done on this spring to stretch it through an additional distance ‘S’ will be

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answer is 30.

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Detailed Solution

12kS2=10 J (given in the problem)12k(2S)2−(S)2=3×12kS2= 3 × 10 = 30 J

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