First slide

Bohr's atom model

Question

The potential energy of an electron in the fifth orbit of hydrogen atom is

Easy

A

0.54 eV
B

-0.54 eV
C

1.08 eV
D

-1.08 eV

Solution

$T E = - \frac{13.6}{n^{2}} = - \frac{13.6}{5^{2}} eV = - 0.544 eV ∴ P E = 2 T E = - 2 \times 0.544 eV = - 1.088 eV$

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