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Q.

The potential energy for a force field F→ is given by U(x, y) = cos(x + y). The force acting on a particle at position given by coordinates (0, π/4) is

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a

−12(i^+j^)

b

12(i^+j^)

c

12i^+32j^

d

12i^−32j^

answer is B.

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Detailed Solution

Fx=−∂U∂X=sin⁡(x+y)=12Fy=−∂U∂Y=sin⁡(x+y)=12F→=12(i^+j^)

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