The potential energy of a force field is given by U=sin(x+y). The force acting on the particle at position π4,π4 is
-12(i^+j^)
12(i^+j^)
−12i^
0
F→=−∂U∂xi^−∂U∂yj^−∂U∂zk^F→=−cos(x+y)i^−cos(x+y)j^F→=−cos(x+y)(i^+j^)Atπ4,π4F→=−cosπ4+π4(i→+j^ F→=0→ F=0