The potential energy (in joule) of a body of mass 2 kg moving in the x-y plane is given by U = 6x + 8y where the position coordinates x and y are measured in metre. If the body is at rest at point (6 m, 4m) at time t = 0, it will cross the y-axis at time t equal to

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answer is B.

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Detailed Solution

Fx=-dUdx=ddx(6x+8y)=-6Fy=-dUdy=-8ax=62=3,ay=82=4after time (t) x=x0−12axt2=6−12×3×t2y=y0−12ayt2=4−2t2body crosses y axis at x = 06−32t2=0,t=2sec