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The potential energy  in joule of a particle of mass 1 kg moving in X-Y plane obeys the law ϕ=3x+4y . Here x and y are in meters. If the particle is at rest at (6m, 8m) at time t=0 , then the work done by conservative force on the particle from initial position to the instant when it comes to origin

         

a
50 J
b
– 50 J
c
25 J
d
– 25 J

detailed solution

Correct option is A

relation between potential energy and the conservative force is F= –dUdrhere U= 3x+4y    then    F⇀ =-3i^-4j^ again displacement is (6,8) to (0,0)  then s⇀= -6i^ -8j^so work done =F⇀.s⇀ =-3i^ -4j^  .-6i^ -8j^ =50

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