Questions
The potential energy of a 1 Kg particle free move along the x-axis is given by . The total mechanical energy of the particle Then ,the maximum speed (in m/s) is
detailed solution
Correct option is B
U=x44-x22 F=dUdx=4x34-2x2=x3-x 0=xx2-1 x=0,±1 d2Udx2=3x2-1 For x=±1, d2Udx2=+iveK.Emax=ET−UminUmin(±1)=−1/4JKEmax=121v2=9/4J ⇒v=32JTalk to our academic expert!
Similar Questions
A 15 g ball is shot from a spring gun whose spring has a force constant of 600 N/m. The spring is compressed by 5 cm. The greatest possible horizontal range of the ball for this compression is (g = 10 m/s2)
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