First slide

Work done by Diff type of forces

Question

The potential energy of a long spring when stretched by 2 cm is U. If the spring is stretched by 8 cm the potential energy stored in it is :

Moderate

A

4U
B

8U
C

16U
D

$\frac{U}{4}$

Solution

$U = \frac{1}{2} {kx}^{2} \Rightarrow U' = U {(\frac{x'}{x})}^{2} = U \cdot {(\frac{8}{2})}^{2} = 16 U$

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