Q.

The potential energy of a long spring when stretched by 2 cm is U. If the spring is stretched by 8 cm the potential energy stored in it is :

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a

4U

b

8U

c

16U

d

U4

answer is C.

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Detailed Solution

U=12kx2   ⇒   U'=Ux'x2=U·822=16U
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Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
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