The potential energy of a particle is determined by the expression U = a (x2+y2), where α is a positive constant. The particle begins to move from a point with coordinates (3,3), only under the action of potential field force. Then its kinetic energy T at the instant when the particle is at a point with the coordinates (1, 1) is
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a
8α
b
24α
c
16α
d
Zero
answer is C.
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Detailed Solution
As the particle moves only under the action of conservative force, its mechanical energy must be conserve(d) So∆T + ∆U = 0 (T stands for kinetic energy)or ∆T = -∆U = Ui - Uf=α(32 + 32) -α(12 + 12) = 16α