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Q.

The potential energy of a particle executing SHM along the x-axis is given by U=U0−U0cos⁡ax. What is the period of oscillation?

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a

2πmaU0

b

2πU0ma

c

2πamU0

d

2πmaU0

answer is C.

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Detailed Solution

U=U0−U0cos⁡axF=−dUdx=−U0asin⁡ax=md2xdt2 For small values of x ,  md2xdt2=−U0a2  This is the equation of SHM ⇒T=2πamU0
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