Questions
Potential energy of a particle executing SHM is U at an instant. Magnitude of acceleration is a at the same instant. If x is the magnitude of displacement of the particle
a
U is proportional to x
b
a is proportional to x
c
U is proportional to x2
d
Both (2) and (3)
detailed solution
Correct option is D
For simple harmonic motion, the potential energy can be written as U=12Kx2; ∴U α x2 . Differentiating with respect to x we get dUdx=−Kx.Here dUdx is the force due to simple harmonic motion which can be equated to ma. Hence we get ma=−Kx.From this we can conclude that a=−Kxm ∴a α xTalk to our academic expert!
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When the displacement is half the amplitude, the ratio of potential energy to the total energy is
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