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Q.

The potential energy of a particle in force filed is U = Ar2−Br  where A and B are positive constants and ‘r’ is the distance of particle from the centre of the field . For stable equilibrium , the distance of the particle is

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a

A/B

b

B/A

c

B2A

d

2A/B

answer is D.

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Detailed Solution

for stable equilibrium F=-dUdr=0 -ddrAr2-Br=0 A(-2r-3)-B(-1r-2)=0 ⇒r=2AB
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The potential energy of a particle in force filed is U = Ar2−Br  where A and B are positive constants and ‘r’ is the distance of particle from the centre of the field . For stable equilibrium , the distance of the particle is