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Q.

The potential energy of a particle in a force filed is   u =Ar2-Br   where A and B are positive  constants and 'r' is the distance of particle from the centre of the field. For stable equilibrium,   the distance of the particle

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a

A/B

b

B/A

c

B2A

d

2AB

answer is D.

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Detailed Solution

For stable equilibrium  dudr= 0-2 A r3+Br2 =0r =2AB
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