The potential energy of a particle in a force filed is u =Ar2-Br where A and B are positive constants and 'r' is the distance of particle from the centre of the field. For stable equilibrium, the distance of the particle
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a
A/B
b
B/A
c
B2A
d
2AB
answer is D.
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Detailed Solution
For stable equilibrium dudr= 0-2 A r3+Br2 =0r =2AB