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Q.

The potential energy of a particle of mass ‘m’ free to move along x-axis is given byU=12 kx2  for x < 0 and U = 0 forx≥0 (x denotes the x-coordinate of the particle and ‘k’ is a positive constant). If the total mechanical energy of the particle is ‘E’, then its speed atx=−2Ek  is

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a

Zero

b

2Em

c

Em

d

E2m

answer is A.

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Detailed Solution

E=K.E +P.E⇒K.E=E−12Kx2 K.E  at  x=−2EK  is  KE=E−E=0
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