Questions
The potential energy of a particle of mass m is given by
λ1 and λ2 are the de-Broglie wavelengths of the particle, when 0 x
1 and x > 1 respectively. If the total energy of particle is 2E0 ,the ratio
will be
detailed solution
Correct option is C
K.E.= 2 E0– E0 = E0 (for 0 x 1) ⇒ K.E. = 2 E0 (for x > 1) ⇒Talk to our academic expert!
Similar Questions
An electron is orbiting in 4th energy state in a hydrogen atom. The de-Broglie wavelength associated with this electron is nearly equal to
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
