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Q.

The potential energy of a particle of mass m is given byλ1 and λ2 are the de-Broglie wavelengths of the particle, when 0  x  1 and x > 1 respectively. If the total energy of particle is 2E0 ,the ratio   will be

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a

2

b

1

c

d

answer is C.

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Detailed Solution

K.E.= 2 E0– E0 = E0  (for 0  x  1)  ⇒ K.E. = 2 E0 (for x > 1) ⇒
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