The potential energy of a particle of mass m is given byλ1 and λ2 are the de-Broglie wavelengths of the particle, when 0 x 1 and x > 1 respectively. If the total energy of particle is 2E0 ,the ratio will be
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a
2
b
1
c
d
answer is C.
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Detailed Solution
K.E.= 2 E0– E0 = E0 (for 0 x 1) ⇒ K.E. = 2 E0 (for x > 1) ⇒