The potential energy of a particle of mass m is given by U(x)=E0;0≤x≤10;x>1 . λ1 and λ2 are the de Broglie wavelengths of the particle, when 0 ≤ x ≤ 1 and x > 1 respectively. If the total energy of particle is 2E0,the ratio λ1λ2 will be
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a
2
b
1
c
2
d
12
answer is C.
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Detailed Solution
K.E=2E0−E0=E0( for 0≤x≤1) ⇒λ1=h2mE0 K.E. =2E0( for x>1) ⇒λ2=h4mE0 ⇒λ1λ2=2
The potential energy of a particle of mass m is given by U(x)=E0;0≤x≤10;x>1 . λ1 and λ2 are the de Broglie wavelengths of the particle, when 0 ≤ x ≤ 1 and x > 1 respectively. If the total energy of particle is 2E0,the ratio λ1λ2 will be