The potential energy of a particle varies with distance x as U=Ax1/2x2+B, where A and B are constants. The dimensional formula for A x B is

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M1L7/2T−2

M1L11/2T−2

M1L5/2T−2

M1L9/2T−2

answer is B.

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Detailed Solution

Here x2 has the dimensions of L2,B=L2 Also ML2T−2=AL1/2L2 or A=ML7/2T−2∴ A×B=ML11/2T−2

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