Questions
The potential energy of a particle with displacement X is U(X). The motion is simple harmonic, when (K is a positive constant)
a
U=−KX22
b
U=KX2
c
U=K
d
U=KX
detailed solution
Correct option is A
F=− kx ⇒dW=Fdx=− kxdxSo ∫ 0 WdW=∫ 0 x−kx dx ⇒W=U=−12kx2Talk to our academic expert!
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When the displacement is half the amplitude, the ratio of potential energy to the total energy is
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