The potential energy of a positive in a certain field is given by U=ar2−br, where a and b are positive constant and r is the distance from centre of field. The equilibrium position of particle in this field is given by r0=n.ab. The value of n is
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answer is 2.
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Detailed Solution
F→=−dUdr At equilibrium F=0⇒−dUdr=0−ddrar2−br=0⇒−−2ar3+br2=0br2=2ar3r=2ab⇒n=2