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Q.

The potential energy of a projectile at its maximum height is equal to its kinetic energy there. If the velocity of projection is 20ms-1 , its time of flight is (g=10ms-2 )

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a

2s

b

2 2s

c

12 s

d

12 s

answer is B.

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Detailed Solution

P.E=K.E⇒12mu2sin2θ=12mu2cos2θuse  T=2usinθg
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