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The potential energy (in SI units) of a particle of mass 2 kg in a conservative field is U = 6x - 8y. If the initial velocity of the particle is u→=−1.5i^+2j^, then find the total distance (in m) travelled by the particle in first two seconds.

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answer is 15.

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Detailed Solution

F→=−∂U∂xi^−∂U∂yj^=−6i^+8j^a→=−3i^+4j^ has some direction as that of u→=−1.5i^+2j^|a→|=5,|u→|=52Since u→ and a→ are in same direction, particle will move along a straight line S=52×2+12×5×22=15 m

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The potential energy (in SI units) of a particle of mass 2 kg in a conservative field is U = 6x - 8y. If the initial velocity of the particle is u→=−1.5i^+2j^, then find the total distance (in m) travelled by the particle in first two seconds.