First slide

Work done by Diff type of forces

Question

The potential energy of a spring when stretched through a distance x is 10 J. What is the amount of work done on the same spring to stretch it through an additional distance x?

Easy

A

10 J
B

20 J
C

30 J
D

40 J

Solution

Potential energy of the spring when stretched through a distance x,
$U^{'} = \frac{1}{2} {kx}^{2} = 10 J$
When x becomes 2x, the potential energy will be
$U^{'} = \frac{1}{2} k {(2 x)}^{2} = 4 \times \frac{1}{2} {kx}^{2} = 4 \times 10 = 40 J$
Work done = $U^{'} - U = 40 - 10 = 30 J$

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