The potential energy (U) of gravitational interaction of a point mass m and a thin uniform rod of mass M and length ‘l ’, if they are located along a straight line with a distance ‘a’ between nearest end of the rod and the point mass is

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U=−GMma loge(a+la)

U=GMm (1a−1a+l)

U=−GMml loge(a+la)

U=−GMma

answer is C.

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Detailed Solution

dU=−Gdm.mx=−GmMldxx U=∫dU=GmMl∫aa+ldxx=−GmMllna+la

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